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X^2+26X-1080=0
a = 1; b = 26; c = -1080;
Δ = b2-4ac
Δ = 262-4·1·(-1080)
Δ = 4996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4996}=\sqrt{4*1249}=\sqrt{4}*\sqrt{1249}=2\sqrt{1249}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{1249}}{2*1}=\frac{-26-2\sqrt{1249}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{1249}}{2*1}=\frac{-26+2\sqrt{1249}}{2} $
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